Chen–Raspaud conjecture
Chen–Raspaud conjecture
For every integer , every graph with odd girth and maximum average degree admits a -coloring; that is, there is an assignment of a -element subset of to each vertex of such that adjacent vertices receive disjoint subsets. Here .
Equivalent formulations 1
Other statements of this same problem, merged from separate entries. Each is equivalent to the statement above — proving any one settles them all.
Kneser-graph homomorphism formulation
For every integer , every graph with and admits a graph homomorphism , where is the Kneser graph whose vertices are the -element subsets of and whose edges join disjoint subsets.
Sources & referencesView supporting material
Primary source
Additional references
- A Proof of the Chen–Raspaud Conjecture — arXiv — Qi Wu, Yong Lu
Progress summary
A new unrefereed manuscript claims to prove the conjecture in every dimension covered by it, but the proof has not yet been independently verified.
The Chen–Raspaud conjecture predicts a specific fractional-colouring of graphs satisfying sparse-graph and odd-girth conditions, for every integer . A complete proof would settle a broad family of sparse-graph colouring questions.
Known results
- : Chen and Raspaud.
- : Łyczek, Nazarczuk, and Rzążewski.
- : Choi.
August 2026 claimed proof
Qi Wu and Yong Lu’s manuscript, submitted August 15, claims that every graph with and admits a -colouring, equivalently a homomorphism to , for all . The authors report that ChatGPT 5.6 Pro assisted with strategies, proof checking, and exposition; the manuscript is unrefereed, with no independent verification found.
Current status (as of August 2026): The cases , , and are reported as known, while the all- theorem remains an unverified claim rather than a settled result.
Sources
Solutions 0
Sign in to submit a solution.
No solutions have been posted yet.