Tu–Deng conjecture

For every integer k≥2k\ge 2, let N=2k−1N=2^k-1. For every integer tt with 1≤t≤N−11\le t\le N-1, the number of pairs (a,b)∈{0,1,…,N−1}2(a,b)\in\{0,1,\ldots,N-1\}^2 satisfying a+b≡t(modN)a+b\equiv t\pmod N and wt⁡k(a)+wt⁡k(b)<k\operatorname{wt}_k(a)+\operatorname{wt}_k(b)<k is at most 2k−12^{k-1}, where wt⁡k(x)\operatorname{wt}_k(x) denotes the Hamming weight of the kk-bit binary representation of xx; equivalently, #{(a,b)∈{0,…,N−1}2:a+b≡t(modN), wt⁡k(a)+wt⁡k(b)<k}≤2k−1\#\{(a,b)\in\{0,\ldots,N-1\}^2:a+b\equiv t\pmod N,\ \operatorname{wt}_k(a)+\operatorname{wt}_k(b)<k\}\le 2^{k-1} for all such kk and tt.

References

Primary source

arXiv

Additional references

Progress summary

Refreshed
Claimed solved

A new preprint claims the conjecture is proved, but the result has not yet been independently checked.

The Tu–Deng conjecture asserts that, for N=2k−1N=2^k-1 and 1≤t≤N−11\leq t\leq N-1, the number of pairs satisfying a+b≡t(modN)a+b\equiv t\pmod N and wt⁡(a)+wt⁡(b)<k\operatorname{wt}(a)+\operatorname{wt}(b)<k is at most 2k−12^{k-1}. It is connected to related binary sum-of-digits and coding-theoretic conjectures.

Known results

  • Tu and Deng verified the conjecture for k≤29k\leq 29; Flori extended this to k≤40k\leq 40.
  • Spiegelhofer and Wallner proved it for a set of parameters of asymptotic density one.
  • A 2020 preprint proved the required bound when wt⁡(t)≤10\operatorname{wt}(t)\leq 10.

August 2026 claimed proof

An August 2026 preprint announces a complete proof via cyclic carry solutions and a negative-half-plane bound for an associated enumerator; a daily listing identifies Thomas W. Cusick with a further claimed proof. The claim is unrefereed and has no recorded independent verification. The authors also report a Lean formalization and acknowledge assistance from ChatGPT 5.6 Pro.

Current status (as of August 2026): The conjecture has a complete-proof claim in an unrefereed preprint, but no independent verification is recorded, so the claim remains unconfirmed.

Sources

Solutions 0

No solutions have been posted yet.