Erdős–Selfridge conjecture on prime divisors of consecutive products

Let k4k\geq 4, let nn be an integer, and let p(k)p^{(k)} denote the smallest prime greater than or equal to kk. The product of kk consecutive integers is

(n+1)(n+k).(n+1)\cdots(n+k).

Erdős–Selfridge conjecture. If n+kp(k)n+k\geq p^{(k)}, then there is a prime greater than kk which divides (n+1)(n+k)(n+1)\cdots(n+k) to the first power.

This conjecture is attributed in the source to Erdős and Selfridge and is stated because it implies the index divisor free prime conjecture when k5k\geq 5 and kk is not prime. Its resolution status is not specified in the supplied text.

Sources & referencesView supporting material

Primary source

Heidi Benham, Alexander Galarraga, Benjamin Hutz, Joey Lupo, Wayne Peng and Adam Towsley, “Integrality and Thurston Rigidity for Bicritical PCF Polynomials”, arXiv:2212.02558 (2022).

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