Narayana refinement conjecture for the sets An{\cal A}_n

From papers

Suppose that n2n\ge 2, and let DnkD_{nk} be the number of elements of An{\cal A}_n for which equality holds for kk of the relevant inequalities. Let N(n,k)N(n,k) denote the Narayana number

N(n,k)=1n(nk)(nk1).N(n,k)=\frac{1}{n}\binom{n}{k}\binom{n}{k-1}.

Narayana refinement conjecture. The number DnkD_{nk} is divisible by

i=0n31i+1(2ii),\prod_{i=0}^{n-3}\frac{1}{i+1}\binom{2i}{i},

and the quotient is the Narayana number N(n2,k)N(n-2,k).

This is presented as a stronger combinatorial refinement of the volume conjecture, classifying the elements of An{\cal A}_n by the number of equalities they satisfy. The paper states that it has not been proved.

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Sources & referencesView supporting material

Primary source

Clara S. Chan, David P. Robbins and David S. Yuen, “On the volume of a certain polytope”, arXiv:math/9810154 (1998).

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