Conjectural equality of diagonal numerator-denominator gcds

Let N(Cn,2;s,t)N(C_{n,2};s,t) and D(Cn,2;s,t)D(C_{n,2};s,t), respectively N(Tn,2;s,t)N(T_{n,2};s,t) and D(Tn,2;s,t)D(T_{n,2};s,t), be the numerators and denominators of the corresponding bigraded Poincaré series.

Diagonal-gcd conjecture. For all nn,

gcd(N(Cn,2;t,t),D(Cn,2;t,t))=gcd(N(Tn,2;t,t),D(Tn,2;t,t)).\gcd\left( N(C_{n,2};t,t),D(C_{n,2};t,t) \right)=\gcd\left( N(T_{n,2};t,t),D(T_{n,2};t,t) \right).

This is the fourth conjecture in the paper's list and is reported to hold for n6n\le6 by computation. Its validity for arbitrary nn is not resolved in the supplied source.

Sources & referencesView supporting material

Primary source

Dragomir Z. Djokovic, “Poincare series of some pure and mixed trace algebras of two generic matrices”, arXiv:math/0609262 (2006).

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