The discriminant-controlled polynomial congruence conjecture

Fix an integer d2d\geq2. For a monic polynomial f(x)Z[x]f(x)\in\mathbb Z[x], consider integers bb such that whenever p2p^2 divides bb, the prime pp does not divide the discriminant of ff. The polynomial congruence conjecture. For every ϵ>0\epsilon>0, there is a constant N(d,ϵ)N(d,\epsilon) such that there are at most N(d,ϵ)N(d,\epsilon) integers nn with

0n<b1ϵ,f(n)0(modb).0\le n<b^{1-\epsilon},\qquad f(n)\equiv0\pmod b.

The source presents this as an open variant of the bounded-residue-set conjecture, motivated by the obstruction from repeated roots modulo prime powers.

Sources & referencesView supporting material

Primary source

Javier Cilleruelo and Andrew Granville, “Lattice points on circles, squares in arithmetic progressions and sumsets of squares”, arXiv:math/0608109 (2006).

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