Conjecture on positive definiteness of the invariant-theoretic matrix Xi

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For positive integers nn and kk, let STab⁡((kn))\operatorname{STab}((k^n)) be the set of standard tableaux of rectangular shape (kn)(k^n). For each T∈STab⁡((kn))T\in\operatorname{STab}((k^n)), let DT(X)=wrdet⁡k(g(T)−1⋅X)D_T(X)=\operatorname{wrdet}_{k}(g(T)^{-1}\cdot X), and define the f(kn)×f(kn)f^{(k^n)}\times f^{(k^n)} matrix

Ξn,k=(φn,k(g(T)−1g(S)))S,T∈STab⁡((kn)).\Xi_{n,k}=\bigl(\varphi_{n,k}(g(T)^{-1}g(S))\bigr)_{S,T\in\operatorname{STab}((k^n))}.

Here φn,k\varphi_{n,k} is the function introduced in the preceding construction, and Mn,kTkn,det⁡=C[Skn]⋅wrdet⁡kM_{n,k}^{T_{kn},\operatorname{det}}=\mathbb{C}[\mathfrak{S}_{kn}]\cdot\operatorname{wrdet}_{k}. Positive-definiteness conjecture. The matrix Ξn,k\Xi_{n,k} is positive definite; in particular, det⁡Ξn,k>0\operatorname{det}\Xi_{n,k}>0. Equivalently, {DT(X)}T∈STab⁡((kn))\{D_T(X)\}_{T\in\operatorname{STab}((k^n))} is another basis of Mn,kTkn,det⁡M_{n,k}^{T_{kn},\operatorname{det}}. The preceding discussion establishes only that Ξn,k\Xi_{n,k} is symmetric and positive semidefinite, so the asserted strict positivity and basis property remain conjectural.

References

Primary source

Kazufumi Kimoto and Masato Wakayama, “Invariant theory for singular α-determinants”, arXiv:math/0603699 (2007).

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