The binomial alternating-sum gcd conjecture

From papers

For positive integers mm and nn, define the sequence of integers

Ar(n)=k=nn(1)k(2nn+k)r.A_r(n)=\sum_{k=-n}^n(-1)^k{2n\choose n+k}^r.

The alternating-sum gcd conjecture. For all positive mm and nn,

gcd(Am(n),Am+1(n),)=(2nn).\gcd\bigl(A_m(n),A_{m+1}(n),\ldots\bigr)={2n\choose n}.

Here the greatest common divisor is taken over all exponents r=m,m+1,r=m,m+1,\ldots. This is presented as one of the paper’s open problems, and no general proof or disproof is supplied.

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Sources & referencesView supporting material

Primary source

Victor J. W. Guo, Frederic Jouhet and Jiang Zeng, “Factors of Alternating Sums of Products of Binomial and q-Binomial Coefficients”, arXiv:math/0511635 (2007).

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