The binomial alternating-sum gcd conjecture

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For positive integers mm and nn, define the sequence of integers

Ar(n)=∑k=−nn(−1)k(2nn+k)r.A_r(n)=\sum_{k=-n}^n(-1)^k{2n\choose n+k}^r.

The alternating-sum gcd conjecture. For all positive mm and nn,

gcd⁡(Am(n),Am+1(n),…)=(2nn).\gcd\bigl(A_m(n),A_{m+1}(n),\ldots\bigr)={2n\choose n}.

Here the greatest common divisor is taken over all exponents r=m,m+1,…r=m,m+1,\ldots. This is presented as one of the paper’s open problems, and no general proof or disproof is supplied.

References

Primary source

Victor J. W. Guo, Frederic Jouhet and Jiang Zeng, “Factors of Alternating Sums of Products of Binomial and q-Binomial Coefficients”, arXiv:math/0511635 (2007).

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