The density conjecture for the integrated superBrownian excursion

Let μISE\mu_{\mathrm{ISE}} be the integrated superBrownian excursion measure on R\mathbb{R}, and let Y(λ)Y(\lambda) be the non-negative random variable whose law is specified by the local limit theorem. Write Leb\operatorname{Leb} for Lebesgue measure on R\mathbb{R}. The density conjecture. There exists a random continuous process fISE(λ)f_{\mathrm{ISE}}(\lambda), defined for λR\lambda\in\mathbb{R}, such that

μISE=fISELeb,\mu_{\mathrm{ISE}}=f_{\mathrm{ISE}}\operatorname{Leb},

and

fISE(λ)=d12Y(λ2).f_{\mathrm{ISE}}(\lambda)\stackrel{\mathrm{d}}{=}\frac{1}{\sqrt{2}}Y\left(\frac{|\lambda|}{\sqrt{2}}\right).

The conjecture asserts absolute continuity and continuity of the ISE density, with its one-point distributions determined by the local limit law for embedded trees. The existence of such a continuous density was not established in the source, so the conjecture remains open.

Sources & referencesView supporting material

Primary source

Mireille Bousquet-Mélou, “Limit laws for embedded trees. Applications to the integrated superBrownian excursion”, arXiv:math/0501266 (2005).

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