Multiplier-group subgroup conjecture for algebraic quasiperiodic flows
Let be the -torus, let be a quasiperiodic flow on generated by a constant vector field , and let be a real algebraic number field of degree over . Suppose that there is a nonzero real number such that the components of form a basis of over . The multiplier-group subgroup conjecture. The multiplier group of is a subgroup of the group of units of the ring of integers in . This conjecture concerns the arithmetic structure of the smooth-conjugacy invariant associated with a quasiperiodic flow; the paper later says that the conjecture is reformulated and proved, so its resolution should be checked against the cited theorem.
References
Primary source
Lennard F. Bakker, “Quasiperiodic Flows and Algebraic Number Fields”, arXiv:math/0307389 (2003).
Progress summary
A 2003 paper claims to prove the conjecture, but the supplied evidence contains no independent verification of that claim.
Lennard F. Bakker formulated the multiplier-group subgroup conjecture for algebraic quasiperiodic flows. His 30 July 2003 paper says the conjectures are reformulated and proved in Theorems and , which directly concerns the stated one-way inclusion.
Known results
- Bakker, 2004: a semiconjugacy theorem gives a finite-index subgroup relation for multiplier groups, partially supporting a broader converse conjecture.
- Bakker, 2005: the broader characterization is described as partially validated for and fully validated for ; this is distinct from the stated subgroup assertion.
30 July 2003 claimed proof
Bakker’s paper explicitly claims to reformulate and prove the relevant conjectures, with Theorems and supplying the stated result. The scan found no subsequent error report, retraction, referee assessment, or independent verification.
Current status (as of September 2026): the conjecture has a direct claimed proof in Bakker’s 2003 paper, but that proof is not independently verified in the supplied evidence; the broader converse characterization remains only partially established.
Sources
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Solutions 0
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