Absolute convergence conjecture for sewn supergeometric tubes

From papers

Let Q1SK(m)Q_1\in SK(m) and Q2SK(n)Q_2\in SK(n) be supergeometric data of the forms

Q1=((z1,θ1),,(zm1,θm1);(A(0),M(0)),(a(1),A(1),M(1)),,(a(m),A(m),M(m))),Q_1=((z_1,\theta_1),\ldots,(z_{m-1},\theta_{m-1});(A^{(0)},M^{(0)}),(a^{(1)},A^{(1)},M^{(1)}),\ldots,(a^{(m)},A^{(m)},M^{(m)})),

and

Q2=((z1,θ1),,(zn1,θn1);(B(0),N(0)),(b(1),B(1),N(1)),,(b(n),B(n),N(n))).Q_2=((z_1',\theta_1'),\ldots,(z_{n-1}',\theta_{n-1}');(B^{(0)},N^{(0)}),(b^{(1)},B^{(1)},N^{(1)}),\ldots,(b^{(n)},B^{(n)},N^{(n)})).

Here SK(k)SK(k) denotes the space of supergeometric configurations with kk tubes, and Γ\Gamma and cc are the quantities occurring in the sewing construction. Absolute convergence conjecture. If the ii-th tube of Q1Q_1 can be sewn with the 00-th tube of Q2Q_2, then the t1/2t^{1/2}-series

eΓ(t1/2a(i),A(i),M(i),B(0),N(0))ce^{\Gamma(t^{-1/2}a^{(i)},A^{(i)},M^{(i)},B^{(0)},N^{(0)})c}

is absolutely convergent at t1/2=1t^{1/2}=1. The conjecture is needed for the stated isomorphism theorem in the nontrivial positive-central-charge case; the theorem holds without it when the relevant Neveu–Schwarz representation has zero central charge. Its status is not resolved in the supplied source context.

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Sources & referencesView supporting material

Primary source

Katrina Deane Barron, “The notion of N=1 supergeometric vertex operator superalgebra and the isomorphism theorem”, arXiv:math/0301273 (2003).

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