Schmutz Schaller's counting-function conjecture for square and hexagonal lattices

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For j≥1j\geq 1, let bj(n)=1b_j(n)=1 if nn is represented by X2+jY2X^2+jY^2, and bj(n)=0b_j(n)=0 otherwise. Define

Bi(x)=∑n≤xbi(n),i∈{1,3}.B_i(x)=\sum_{n\leq x}b_i(n),\qquad i\in\{1,3\}.

Schmutz Schaller's counting-function conjecture. For every xx, one has

B1(x)≥B3(x).B_1(x)\geq B_3(x).

This is an equivalent reformulation of the square-versus-hexagonal lattice conjecture. The paper proves the inequality for every xx, so the conjecture is solved.

References

Primary source

Pieter Moree and Herman J. J. te Riele, “The hexagonal versus the square lattice”, arXiv:math/0204332 (2002).

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