The factorization conjecture for Alexander polynomials of equivariant slice knots

Let KK be a qq-equivariant slice knot with Murasugi polynomial ΔZ/q(g,t)\Delta_{{\bf Z}/q}(g,t). The polynomial ring Z[Z/q×Z]{\bf Z}[{\bf Z}/q\times {\bf Z}] is used, and the factorization condition is that there are nonzero polynomials a(g,t)a(g,t) and b(g,t)b(g,t) satisfying

ΔZ/q(g,t)b(g,t)b(g1,t1)=a(g,t)a(g1,t1),\Delta_{{\bf Z}/q}(g,t)b(g,t)b(g^{-1},t^{-1})=a(g,t)a(g^{-1},t^{-1}),

and a(g,1)=b(g,1)=1a(g,1)=b(g,1)=1.

Factorization conjecture. Alexander polynomials of equivariant slice knots satisfy this factorization condition with b(g,t)=1b(g,t)=1.

The preceding theorem proves the displayed factorization with an auxiliary factor b(g,t)b(g,t) for equivariant slice knots, while the corresponding condition with b(g,t)=1b(g,t)=1 is known for equivariant ribbon knots. The conjecture asserts that the extra factor is unnecessary for all equivariant slice knots; the paper gives an example showing that algebraic considerations alone do not force this conclusion.

Sources & referencesView supporting material

Primary source

James F. Davis and Swatee Naik, “Alexander polynomials of equivariant slice and ribbon knots in S^3”, arXiv:math/0201179 (2002).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.