The twisted Weyl-vector formula for twisted loop algebras

About 22 years old · traced to

Let g~\widetilde{\mathfrak{g}} be a twisted loop algebra with ϵ(h)=0\epsilon(\mathfrak{h})=0. Let ρ^\widehat{\rho} be the Weyl vector determined by the simple roots of g~\widetilde{\mathfrak{g}} through

2(ρ^∣αi^)=(αi^∣αi^).2(\widehat{\rho}\mid\widehat{\alpha_i})=(\widehat{\alpha_i}\mid\widehat{\alpha_i}).

For each positive root α∈Δ+\alpha\in\Delta_+, write pαp_\alpha for its parity and let ϵα≡ϵ(uα)\epsilon_\alpha\equiv\epsilon(u_\alpha). Twisted Weyl-vector formula. The Weyl vector is

ρ^=(ρ~,h∨,0),\widehat{\rho}=(\widetilde{\rho},h^\lor,0),

where

ρ~=12∑α∈Δ+(−1)pαα(1−2ϵα).\widetilde{\rho}=\frac{1}{2}\sum_{\alpha\in\Delta_+}(-1)^{p_\alpha}\alpha(1-2\epsilon_\alpha).

This identifies the affine Weyl vector in the twisted case with a finite-dimensional “twisted rho” together with its h∨h^\lor and DD components; the source provides no resolution or further evidence, so the claim is left open.

References

Primary source

Boris Noyvert, “Ramond sector of superconformal algebras via quantum reduction”, arXiv:math-ph/0408061 (2005).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.