Ground-state transverse matrix-element formula conjecture

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Let N=2n+1N=2n+1 be odd, let ∣Sz=±1/2⟩|S_z=\pm1/2\rangle denote the two ground states, and define the transverse matrix element

M=⟨Sz=1/2∣σjx∣Sz=−1/2⟩.M=\langle S_z=1/2\mid\sigma^x_j\mid S_z=-1/2\rangle.

Transverse matrix-element conjecture. The first-order splitting matrix element satisfies

(2n+1)M=4⋅7⋯(3n+1)2⋅5⋯(3n−1).(2n+1)M=\frac{4\cdot7\cdots(3n+1)}{2\cdot5\cdots(3n-1)}.

The formula agrees with the data reported in the paper, but no proof or general resolution is supplied.

References

Primary source

A. V. Razumov and Yu. G. Stroganov, “Spin chains and combinatorics”, arXiv:cond-mat/0012141 (2000).

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