The mod 8 congruence conjecture for the 2-color overpartition function

From papers

Let p(n)\overline{p}_{\ell}(n) denote the 22-color overpartition function, where \ell is a positive integer, and let n0n\ge0. The mod 8 congruence conjecture. For all 0,1(mod4)\ell\equiv0,1\pmod4 and n0n\ge0,

p(4n+3)0(mod8).\overline{p}_{\ell}(4n+3)\equiv0\pmod8.

The case 0(mod8)\ell\equiv0\pmod8 is established by the paper's Corollary 1, while the remaining cases are supported by numerical evidence and remain open.

Progress summary

Open

The conjecture remains open: one family of cases is proved, while the others have only numerical support.

The conjecture predicts that the relevant counting function vanishes modulo 88 at every index of the form 4n+34n+3 whenever \ell is congruent to 00 or 11 modulo 44. The recent literature records a proof only for the subfamily 0(mod8)\ell\equiv0\pmod8; the remaining cases are explicitly left open.

Known results

  • 0(mod8)\ell\equiv0\pmod8: proved in the cited paper via a corollary; the cases 1(mod4)\ell\equiv1\pmod4 and 4(mod8)\ell\equiv4\pmod8 remain supported only by computation.

July 2026 paper

H. S. Sumanth Bharadwaj, N. Sujatha, and S. Chandankumar state the full conjecture in their paper on arithmetic properties of the 22-color overpartition function, but report no proof beyond 0(mod8)\ell\equiv0\pmod8 and describe the remaining cases as numerical evidence. No counterexample, claimed proof, or verification was found.

Current status (as of August 2026): The congruence is proved for 0(mod8)\ell\equiv0\pmod8, while the cases 1(mod4)\ell\equiv1\pmod4 and 4(mod8)\ell\equiv4\pmod8 remain open.

Sources
Sources & referencesView supporting material

Primary source

H. S. Sumanth Bharadwaj, N. Sujatha and S. Chandankumar, “Arithmetic properties of the 2-color overpartition function p_(n)”, arXiv:2607.16608 (2026).

Solutions 1

Proof

Let

fd(q)=j1(1qdj).f_d(q)=\prod_{j\ge1}(1-q^{dj}).

The defining generating function is

P(q)=n0p(n)qn=f2(q)f2(q)f1(q)2f(q)2.P_\ell(q) = \sum_{n\ge0}\overline p_\ell(n)q^n = \frac{f_2(q)f_{2\ell}(q)} {f_1(q)^2f_\ell(q)^2}.

Jacobi's identity gives

φ(q)=f1(q)2f2(q),\varphi(-q)=\frac{f_1(q)^2}{f_2(q)},

and therefore

P(q)=1φ(q)φ(q).P_\ell(q) = \frac1{\varphi(-q)\varphi(-q^\ell)}.

Write

U(q)=j1(1)jqj2,V(q)=U(q),U(q)=\sum_{j\ge1}(-1)^jq^{j^2}, \qquad V(q)=U(q^\ell),

so that

φ(q)=1+2U(q),φ(q)=1+2V(q).\varphi(-q)=1+2U(q),\qquad \varphi(-q^\ell)=1+2V(q).

Expanding both inverses coefficientwise modulo 88 yields

P(q)=(1+2U)1(1+2V)112(U+V)+4(U2+UV+V2)(mod8).(1)\begin{aligned} P_\ell(q) &=(1+2U)^{-1}(1+2V)^{-1}\\ &\equiv 1-2(U+V)+4(U^2+UV+V^2) \pmod8. \tag{1} \end{aligned}

Suppose

0 or 1(mod4).\ell\equiv0\ \text{or}\ 1\pmod4.

Every exponent in UU is a square and hence belongs to

{0,1}(mod4).\{0,1\}\pmod4.

Every exponent in VV is \ell times a square, and therefore likewise belongs to {0,1}(mod4)\{0,1\}\pmod4. Consequently the exponents in the linear terms U,VU,V belong to {0,1}(mod4)\{0,1\}\pmod4, while those in the quadratic terms U2,UV,V2U^2,UV,V^2 belong to

{0,1,2}(mod4).\{0,1,2\}\pmod4.

None is congruent to 3(mod4)3\pmod4. Taking the coefficient of q4n+3q^{4n+3} in (1) proves

p(4n+3)0(mod8)\boxed{\overline p_\ell(4n+3)\equiv0\pmod8}

for every n0n\ge0 and every positive 0,1(mod4)\ell\equiv0,1\pmod4, establishing the full conjecture.

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