Conjecture on non-full-weight cyclic codes over F3\mathbb F_3

Let n>3n>3 be a prime, and let ordn(3)\operatorname{ord}_n(3) denote the multiplicative order of 33 modulo nn. Set

r=n1ordn(3).r=\frac{n-1}{\operatorname{ord}_n(3)}.

Let N(n,3)\mathcal N(n,3) denote the family of cyclic codes over F3\mathbb F_3 containing no full-weight codeword. The cyclic-code counting conjecture. If ordn(3)\operatorname{ord}_n(3) is odd, then

N(n,3)=j=0r2(rj).|\mathcal N(n,3)|=\sum_{j=0}^{\frac r2}\binom{r}{j}.

The formula refines a lower bound for N(n,3)|\mathcal N(n,3)|; the case n=13n=13 gives 1111 cyclic codes, while the conjecture remains unproved in the stated generality.

Sources & referencesView supporting material

Primary source

Yangcheng Li and Pingzhi Yuan, “Cyclic Codes and Cyclically Covering Subspaces over Finite Fields”, arXiv:2607.02239 (2026).

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