The irreducible-component conjecture for Kottwitz–Viehmann varieties

Let GG be the reductive group defining the Kottwitz–Viehmann variety, let FF be its base field, let TT be a maximal torus, and let G(F)rsG(F)^{\mathrm{rs}} denote the regular semisimple locus. For γG(F)rs\gamma\in G(F)^{\mathrm{rs}} and λX(T)+\lambda\in X_*(T)_+, let νγX(T)Q,+\nu_\gamma\in X_*(T)_{\mathbb{Q},+} be the Newton point and let μX(T)+\mu\in X_*(T)_+ be the minimal dominant integral coweight dominating νγ\nu_\gamma. Write XγλX_\gamma^\lambda for the corresponding Kottwitz–Viehmann variety, Gγ(F)G_\gamma(F) for the loop-group centralizer, and Irr\operatorname{Irr} for the set of irreducible components. Let mλμm_{\lambda\mu} denote the dimension of the μ\mu-weight space in the irreducible representation of the Langlands dual group G^\hat{G} with highest weight λ\lambda. Irreducible-component conjecture. The number of irreducible components of the quotient stack [Xγλ/Gγ(F)][X_\gamma^\lambda/G_\gamma(F)], equivalently the number of Gγ(F)G_\gamma(F)-orbits on Irr(Xγλ)\operatorname{Irr}(X_\gamma^\lambda), equals mλμm_{\lambda\mu}:

#Irr[Xγλ/Gγ(F)]=mλμ.\#\operatorname{Irr}[X_\gamma^\lambda/G_\gamma(F)]=m_{\lambda\mu}.

Although XγλX_\gamma^\lambda may have infinitely many irreducible components, the quotient stack always has finitely many. The conjecture proposes a representation-theoretic description of this finite number in terms of a weight multiplicity for the Langlands dual group; no resolution is supplied in the source.

Sources & referencesView supporting material

Primary source

Jingren Chi, “An overview of the geometry of Kottwitz-Viehmann varieties”, arXiv:2606.31078 (2026).

Additional references

2 papers in this index state this conjecture (2017–2026). The statement above is taken from the most recent of them; the others are arXiv:1710.11243.

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.