The converse from left-finite semibricks to brick finiteness

Let $A$ be a finite dimensional $K$-algebra. A semibrick is left finite if it satisfies the left-finiteness condition defined in the surrounding theory, and $A$ is brick finite if it has only finitely many isoclasses of bricks.

Converse conjecture. If every semibrick is left finite, then $A$ is brick finite.

Brick finiteness implies that every semibrick is left finite, and the converse remains an open problem.