Three reversed primes in base 10

Less than 1 year old · traced to

Work in base b=10b=10, and write p←\overleftarrow{p} for the digit reversal of a prime pp. Base-10 ternary reversed-prime conjecture. Every sufficiently large odd integer NN can be expressed as

N=p1←+p2←+p3←.N=\overleftarrow{p_1}+\overleftarrow{p_2}+\overleftarrow{p_3}.

The binary reversed-prime representation fails for infinitely many integers in base 1010, including the obstruction at 6⋅10n6\cdot 10^n. This conjecture is part of the proposed explanation that the reverse Schnirelmann constant in base 1010 should be 44, with even integers requiring four reversed primes.

References

Primary source

Michael Harm and Daniel R. Johnston, “The reverse Goldbach problem and a refined Zsiflaw–Legeis theorem”, arXiv:2605.21876 (2026).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.