Ballantine–Beck–Feigon–Maurischat's ternary-partition recurrence conjecture

From papers

For ternary partitions, let numT(n,x)\operatorname{num}_{\mathcal T}(n,x) denote the associated numerator. Define t(n):numT(n,1)t(n)\coloneq\operatorname{num}_{\mathcal T}(n,1) for n0n\geq 0, with t(0):1t(0)\coloneq 1. Ballantine–Beck–Feigon–Maurischat's ternary-partition recurrence conjecture. For every n0n\geq 0,

t(3n)=t(3n+1)=t(3n+2),t(3n)=t(3n+1)=t(3n+2),

and for every n1n\geq 1,

t(n)=t(3n)t(3n2)22n.t(n)=\frac{t(3n)-t(3n-2)}{2^{2n}}.

In particular, t(1)=t(2)=1t(1)=t(2)=1. The supplied text explains that this is the intended correction of a literally false formulation in the original source; its resolution is not specified here.

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Sources & referencesView supporting material

Primary source

Evan Chen, Ken Ono and Jujian Zhang, “Reciprocals of Partition Polynomials”, arXiv:2605.21718 (2026).

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