Triangular threshold conjecture for simplex layers in the partition graph

From papers

Let GnG_n be the partition graph, let KnK_n be its clique complex, let Lr(n)L_r(n) denote the vertices of local simplex dimension rr, let Δ(n)\Delta(n) be the maximal local simplex dimension, and let τ(r)\tau(r) be the least nn for which the layer Lr(n)L_r(n) is nonempty. Triangular threshold conjecture. For every r0r\ge 0,

τ(r)=1+r(r+1)2.\tau(r)=1+\frac{r(r+1)}{2}.

Equivalently,

Δ(n)=max{r: 1+r(r+1)2n}.\Delta(n)=\max\Bigl\{r:\ 1+\frac{r(r+1)}{2}\le n\Bigr\}.

The formula is suggested by exhaustive computation for n30n\le 30 and predicts the first appearance of successive simplex layers through triangular-number thresholds; its validity for all rr remains open.

Progress summary

Open

The conjecture matches every tested case up to size 30, but no proof or counterexample has been publicly reported.

The conjecture predicts that the first appearance of the rrth simplex layer occurs at τ(r)=1+r(r+1)/2\tau(r)=1+r(r+1)/2, equivalently giving the stated formula for maximal local dimension. It was formulated in a March 2026 arXiv paper as an open problem.

Known results

  • Exhaustive computation through n30n\le 30 gives τ(r)=1,2,4,7,11,16,22,29\tau(r)=1,2,4,7,11,16,22,29 for 0r70\le r\le 7.
  • For 2r72\le r\le 7, the first layer consists of one-cell extensions of the staircase partition δr=(r,r1,,1)\delta_r=(r,r-1,\ldots,1).
  • The source explicitly states that these computations do not constitute a proof.

March 2026 status

A subsequent arXiv paper restated the triangular-threshold formula as a conjecture and reported no proof, counterexample, verification, or refutation; the all-rr statement therefore remains open.

Current status (as of August 2026): The conjecture is computationally verified through n30n\le 30, while its validity for all r0r\ge 0 remains unresolved.

Sources
Sources & referencesView supporting material

Primary source

Fedor B. Lyudogovskiy, “Simplex Stratification and Phase Boundaries in the Partition Graph”, arXiv:2603.23228 (2026).

Solutions 1

Proof

Proof of all triangular thresholds and the maximal-dimension formula

The previously established local corner formulas in arXiv:2603.18696, Corollary 3.4, Proposition 3.7, and Theorem 7.1, are used as known input.

Write

λ=(d1m1,,dkmk),d1>>dk>0,gi=didi+1,dk+1=0.\lambda=(d_1^{m_1},\ldots,d_k^{m_k}), \qquad d_1>\cdots>d_k>0, \qquad g_i=d_i-d_{i+1}, \qquad d_{k+1}=0.

For removable corner ii and addable corner jj, the known corner-incidence matrix is

Mij=11{j=i, mi=1}1{j=i+1, gi=1}.M_{ij} = 1-\mathbf1_{\{j=i,\ m_i=1\}} -\mathbf1_{\{j=i+1,\ g_i=1\}}.

Hence the star capacities are

si=k+11{mi=1}1{gi=1},s_i=k+1-\mathbf1_{\{m_i=1\}}-\mathbf1_{\{g_i=1\}},

and every top capacity is at most kk. Consequently

dimloc(λ)={0,λ=(1),k1,λ=(k,k1,,1), k2,k+1,mi2 and gi2 for some i,k,otherwise.(1)\dim_{\mathrm{loc}}(\lambda)= \begin{cases} 0,&\lambda=(1),\\ k-1,&\lambda=(k,k-1,\ldots,1),\ k\ge2,\\ k+1,&m_i\ge2\text{ and }g_i\ge2\text{ for some }i,\\ k,&\text{otherwise}. \end{cases} \tag{1}

Put ai=mi1a_i=m_i-1, bi=gi1b_i=g_i-1, and Tk=k(k+1)/2T_k=k(k+1)/2. Direct summation gives the exact weight identity

λ=Tk+i=1k(ki+1)ai+i=1kibi+1ijkaibj.(2)|\lambda| = T_k+ \sum_{i=1}^k(k-i+1)a_i + \sum_{i=1}^k i b_i + \sum_{1\le i\le j\le k}a_i b_j. \tag{2}

All terms after TkT_k are nonnegative.

Fix r2r\ge2. If kr2k\le r-2, (1) rules out local dimension at least rr. If kr+1k\ge r+1, (2) gives

λTr+1>Tr+1.|\lambda|\ge T_{r+1}>T_r+1.

If k=rk=r, the staircase itself has dimension r1r-1, so dimension at least rr requires

λTr+1.|\lambda|\ge T_r+1.

Equality occurs only for b1=1b_1=1 or ar=1a_r=1, with all other excess parameters zero.

If k=r1k=r-1, dimension at least rr requires ai,bi1a_i,b_i\ge1 for a common ii. Formula (2) then gives

λTk(ki+1)+i+1=k+2,|\lambda|-T_k \ge(k-i+1)+i+1=k+2,

hence again

λTk+k+2=Tr+1.|\lambda|\ge T_k+k+2=T_r+1.

Equality occurs exactly when ai=bi=1a_i=b_i=1 for one 1ik1\le i\le k, with all other excess parameters zero.

Both equality constructions exist. Therefore

τ(r)=r(r+1)2+1(r2).\boxed{\tau(r)=\frac{r(r+1)}2+1\qquad(r\ge2).}

The exceptional initial layers satisfy τ(0)=1\tau(0)=1 and τ(1)=2\tau(1)=2, as required.

Moreover, for every nTr+1n\ge T_r+1, the partition

(nTr+r,r1,r2,,1)(n-T_r+r,r-1,r-2,\ldots,1)

has exactly rr distinct part sizes and local dimension rr. Conversely, the argument above rules out dimension rr at every smaller size. Hence

Δ(n)=max{r0:r(r+1)2+1n}.\boxed{ \Delta(n)=\max\left\{ r\ge0:\frac{r(r+1)}2+1\le n \right\}. }

This proves every assertion of the triangular-threshold conjecture.

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