Alon–Tarsi conjecture on the parity of Latin squares
Let be a Latin square of order , and define its sign by the product of the signs of its row and column permutations. Let and denote the numbers of even and odd Latin squares, respectively. Alon–Tarsi conjecture. If is even, then
equivalently, the signed enumeration of Latin squares is nonzero. The conjecture remains open in general, with nontrivial cases known for several infinite families of even orders.
References
Primary source
Gergely Bérczi, “Evolving Local Corrections for Global Constructions in Combinatorics”, arXiv:2603.06692 (2026).
Additional references
3 papers in this index state this conjecture (2014–2026). The statement above is taken from the most recent of them; the others are arXiv:2104.00838, arXiv:1412.7574.
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