Fox's slice-ribbon conjecture
Fox's slice-ribbon conjecture
Let be a knot. It is slice if it bounds a smoothly, properly embedded disk in ; it is ribbon if it bounds a disk whose only singularities are ribbon singularities, equivalently if some number of bands can be attached to to produce an unlink. The slice-ribbon conjecture. Every slice knot is ribbon. Every ribbon knot is already known to be slice, so the conjecture is precisely the converse implication and remains a famous open problem.
Sources & referencesView supporting material
Primary source
Ciprian Manolescu, “From knots to four-manifolds”, arXiv:2601.05425 (2026).
Additional references
5 papers in this index state this conjecture (2018–2026). The statement above is taken from the most recent of them; the others are arXiv:2108.10400, arXiv:2101.00865, arXiv:1811.09639, arXiv:1801.07158.
Progress summary
Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.
Solutions 0
Sign in to submit a solution.
No solutions have been posted yet.