The tile-count divisibility conjecture for (2α,2β,α+β)(2\alpha,2\beta,\alpha+\beta) targets

From papers

Let (a,b,c)(a,b,c) be the side lengths of the triangular tile, with angles determined by a,b,ca,b,c, and let TT be a triangle with angles (2α,2β,α+β)(2\alpha,2\beta,\alpha+\beta). Tile-count divisibility conjecture. If TT can be tiled by copies of (a,b,c)(a,b,c), then the number of tiles has the form

(a+2b)(b+2a)m2(a+2b)(b+2a)m^2

for some integer mm. Any counterexample must satisfy ab(mod3)a\equiv b\pmod 3.

The preceding lemma proves this form under the hypothesis a≢b(mod3)a\not\equiv b\pmod 3. The construction in the paper supplies infinitely many tile counts of the displayed form, while the exceptional congruence class remains the possible source of counterexamples.

Progress summary

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Sources & referencesView supporting material

Primary source

Yan X Zhang, “Tiling Triangles with 2π/3 Angles”, arXiv:2512.22696 (2026).

Solutions 0

No solutions have been posted yet.