The reducibility conjecture for falling-factorial polynomials

From papers

For integers ak+3a\geq k+3 and k1k\geq1, define the falling factorial

xk=x(x1)(xk+1).x^{\underline{k}}=x(x-1)\cdots(x-k+1).

Reducibility conjecture. If xka!x^{\underline{k}}-a! is reducible over Z\mathbb{Z}, then (k,a)=(3,6)(k,a)=(3,6), (k,a)=(4,7)(k,a)=(4,7), or there exists an integer tt such that a=t!1a=t!-1 and k=t!tk=t!-t. The source presents this as a conjecture motivated by numerical evidence. The exceptional pairs correspond to the sporadic nontrivial solution (6,7,10)(6,7,10), while the family a=t!1a=t!-1, k=t!tk=t!-t corresponds to class 11 solutions; the general reducibility question remains open.

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Sources & referencesView supporting material

Primary source

Joshua Cooper and Joseph Preuss, “On the sparsity of integers a in solutions to a!b!=c!”, arXiv:2512.03188 (2025).

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