Elliptic identity lifting conjecture for higher-genus multiple zeta values

Let l,k1,,kl1l,k_1,\ldots,k_l\geq1 and let n1,1,,nk1,1,,n1,l,,nkl,l1n_{1,1},\ldots,n_{k_1,1},\ldots,n_{1,l},\ldots,n_{k_l,l}\geq1. Let ωell\omega^{\mathrm{ell}} denote elliptic multiple zeta values and let II be an identity satisfying

I(ωell(n1,11,,nk1,11),,ωell(n1,l1,,nkl,l1))=0.I(\omega^{\mathrm{ell}}(n_{1,1}-1,\ldots,n_{k_1,1}-1),\ldots,\omega^{\mathrm{ell}}(n_{1,l}-1,\ldots,n_{k_l,l}-1))=0.

Elliptic identity lifting conjecture. For any j{1,,h}j\in\{1,\ldots,h\} and any genus h1h\geq1, the corresponding higher-genus multiple zeta values satisfy

I ⁣(ζAj ⁣(jn1,1,,jnk1,1),,ζAj ⁣(jn1,l,,jnkl,l))=0,I\!\left(\zeta_{\mathfrak A_j}\!\left(j^{n_{1,1}},\ldots,j^{n_{k_1,1}}\right),\ldots,\zeta_{\mathfrak A_j}\!\left(j^{n_{1,l}},\ldots,j^{n_{k_l,l}}\right)\right)=0,

with appropriate normalization of the appearing genus-zero multiple zeta values. The conjecture proposes that known identities among elliptic multiple zeta values lift to the corresponding higher-genus values despite the additional sigma terms. The paper reports numerical tests supporting the claim, but no general proof is known.

Sources & referencesView supporting material

Primary source

Konstantin Baune, Johannes Broedel, Egor Im, Zhexian Ji and Yannis Moeckli, “Higher-genus multiple zeta values”, arXiv:2507.21765 (2025).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.