Furdui–Sîntămărian's consecutive harmonic-number product conjecture

About 1 year old · traced to

Let q≥1q\geq 1 be an integer, and let Hk=∑j=1k1jH_k=\sum_{j=1}^k\frac{1}{j} denote the kkth harmonic number. For rational numbers αq,2,αq,3,…,αq,q+2\alpha_{q,2},\alpha_{q,3},\ldots,\alpha_{q,q+2}, consider the corresponding linear combination of zeta values. Furdui–Sîntămărian's conjecture.

∑k=1∞HkHk+1⋯Hk+qk(k+1)⋯(k+q)=αq,2ζ(2)+αq,3ζ(3)+⋯+αq,q+2ζ(q+2).\sum_{k=1}^\infty \frac{H_k H_{k+1}\cdots H_{k+q}}{k(k+1)\cdots(k+q)} = \alpha_{q,2}\zeta(2)+\alpha_{q,3}\zeta(3)+\cdots+\alpha_{q,q+2}\zeta(q+2).

The conjecture predicts that every such consecutive-product series is a rational linear combination of zeta values of weights from 22 through q+2q+2. The case q=2q=2 was computed previously, while the paper's q=3q=3 evaluation produces a term involving ζ(2)ζ(3)\zeta(2)\zeta(3) and therefore does not presently establish or disprove the conjecture.

References

Primary source

Wilson J. Chen and Vincent Nguyen, “A series involving a product of four consecutive harmonic numbers”, arXiv:2507.19502 (2025).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.