The Jiang–Rallis integral point-count conjecture

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Let pp be a prime with p≡5(mod6)p\equiv 5\pmod{6}. Fix b,c∈(Z/pZ)×b,c\in(\mathbf{Z}/p\mathbf{Z})^\times such that

g(u):=−u3+bu+cg(u):=-u^3+bu+c

is irreducible. Consider the triples (r,y,u)∈(Z/pZ)∗×(Z/pZ)×(Z/pZ)(r,y,u)\in(\mathbf{Z}/p\mathbf{Z})^*\times(\mathbf{Z}/p\mathbf{Z})\times(\mathbf{Z}/p\mathbf{Z}) satisfying

g(u)≡3uyr+y3r2−r(modp).g(u)\equiv 3uyr+y^3r^2-r\pmod p.

The Jiang–Rallis integral point-count conjecture. The number of such triples is p2−1p^2-1. This conjecture gives the remaining finite-field count needed to evaluate one of the sub-integrals arising in the Jiang–Rallis computation for F=QF=\mathbf{Q} and p≡5(mod6)p\equiv5\pmod6. It has since been proved by Victor Scharaschkin, so the conjecture is solved.

References

Primary source

Joseph Hundley, Yaniel Rivera Vega and Victor Scharaschkin, “On a Theorem of Jiang and Rallis”, arXiv:2507.18757 (2025).

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