Vertices that never form singleton Delta-sets in finite linear Jaco graphs

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Let Jn(x)J_n(x) be a finite linear Jaco graph and let XX be its Δ\Delta-set. Non-singleton-Delta-vertex conjecture. The vertex subscripts ii for which viv_i does not yield a singleton Δ\Delta-set XX in any finite linear Jaco graph are given by sequence A003622, the Wythoff compound sequence AA, with the stated formula

i=⌊i(1+5)24⌋−1,i=2,3,4,… .i=\left\lfloor\frac{i(1+\sqrt{5})^2}{4}\right\rfloor-1,\qquad i=2,3,4,\dots.

Equivalently, excluding the first term, sequence A003622 is pp-graphical for the parameter identifying the vertex subscript ii when {vi}\{v_i\} is not a Δ\Delta-set, over F={G:G=Jn(x), n=1,2,3,… }\mathcal{F}=\{G:G=J_n(x),\ n=1,2,3,\dots\}. The claim is motivated by the listed exceptional subscripts; its status is unresolved in the supplied source.

References

Primary source

Johan Kok, “Integer sequences with conjectured relation with certain graph parameters of the family of linear Jaco graphs”, arXiv:2507.16500 (2025).

Progress summary

Refreshed
Claimed solved

A reader-posted argument claims a complete proof, but it has not been independently checked, so the question remains unsettled.

The conjecture says that the vertex subscripts that never produce a singleton Δ\Delta-set in any finite linear Jaco graph Jn(x)J_n(x) are the terms of A003622. Johan Kok’s 2025 preprint records this as Conjecture 2.6 and explicitly leaves its proof or disproof for future work.

Posted attempt

A posted argument claims a complete proof: it derives the finite-graph degree formula, characterizes when the maximum-degree set is singleton, and applies Beatty-sequence complementarity to obtain the claimed exceptional indices. The attempt has not been independently verified.

Current status (as of August 2026): A complete proof is claimed in an unverified posted attempt, while the primary 2025 source supplies only experimental evidence; independent verification remains open.

Sources

Solutions 1

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Put φ=(1+5)/2\varphi=(1+\sqrt5)/2 and

bi=⌊i+1φ⌋.b_i=\left\lfloor\frac{i+1}{\varphi}\right\rfloor.

The known indegree formula for the Jaco graph gives the exact finite-graph degree

deg⁡Jn(vi)=min⁡{i,n−bi}.\deg_{J_n}(v_i)=\min\{i,n-b_i\}.

Write d=Δ(Jn)d=\Delta(J_n) and h=n−dh=n-d. Since bib_i is nondecreasing, the complete maximum-degree set is

Xn={vi:i≥d, bi≤h}.X_n=\{v_i:i\ge d,\ b_i\le h\}.

The indices satisfying bi=hb_i=h form the consecutive plateau

⌊hφ⌋,…,⌊(h+1)φ⌋−1.\left\lfloor h\varphi\right\rfloor,\ldots, \left\lfloor(h+1)\varphi\right\rfloor-1.

Consequently Xn={vd}X_n=\{v_d\} if and only if

d=⌊(h+1)φ⌋−1,n=d+h.d=\left\lfloor(h+1)\varphi\right\rfloor-1, \qquad n=d+h.

Thus, apart from the initial singleton {v1}\{v_1\} in J1J_1, the vertex indices that occur as singleton maximum-degree sets are exactly

d=⌊tφ⌋−1,t≥2.d=\left\lfloor t\varphi\right\rfloor-1,\qquad t\ge2.

Beatty's theorem partitions the positive integers into the two disjoint complementary sequences

{⌊tφ⌋:t≥1}and{⌊tφ2⌋:t≥1}.\{\lfloor t\varphi\rfloor:t\ge1\} \quad\text{and}\quad \{\lfloor t\varphi^2\rfloor:t\ge1\}.

Therefore the indices i≥2i\ge2 that never occur as singleton maximum-degree sets are precisely

 i=⌊tφ2⌋−1,t≥2. \boxed{\ i=\left\lfloor t\varphi^2\right\rfloor-1,\qquad t\ge2.\ }

This is exactly the conjectured sequence, with its artificial first term removed.