Sun's integrality conjecture for products of consecutive generalized polynomials

Let Z+{\mathbb Z}^{+} denote the positive integers, and for nZ+n\in{\mathbb Z}^{+} define

wn(α)(x)=k=1nw(n,k)αxk1,w_n^{(\alpha)}(x)=\sum_{k=1}^{n}w(n,k)^{\alpha}x^{k-1},

where

w(n,k)=1k(n1k1)(n+kk1).w(n,k)=\frac{1}{k}\binom{n-1}{k-1}\binom{n+k}{k-1}.

Write wn(x)=wn(1)(x)w_n(x)=w_n^{(1)}(x), let (a,b)(a,b) denote the greatest common divisor of aa and bb, and let Z[x]\mathbb Z[x] denote the ring of polynomials in xx with integer coefficients. Sun's product-integrality conjecture. For any α,m,nZ+\alpha,m,n\in{\mathbb Z}^{+},

2(2,n)n(n+1)(n+2)k=1nk(k+1)(k+2)(wk(α)(x)wk+1(α)(x))mZ[x].\frac{2(2,n)}{n(n+1)(n+2)}\sum_{k=1}^{n}k(k+1)(k+2)\bigl(w_k^{(\alpha)}(x)w_{k+1}^{(\alpha)}(x)\bigr)^m\in\mathbb Z[x].

For any m,nZ+m,n\in{\mathbb Z}^{+},

2(2,n)n(n+1)(n+2)(2x+1)mk=1nk(k+1)(k+2)(wk(x)wk+1(x))mZ[x].\frac{2(2,n)}{n(n+1)(n+2)(2x+1)^m}\sum_{k=1}^{n}k(k+1)(k+2)\bigl(w_k(x)w_{k+1}(x)\bigr)^m\in\mathbb Z[x].

If nZ+n\in{\mathbb Z}^{+} is even, then

4n(n+1)(n+2)(2x+1)3k=1nk(k+1)(k+2)wk(x)wk+1(x)Z[x].\frac{4}{n(n+1)(n+2)(2x+1)^3}\sum_{k=1}^{n}k(k+1)(k+2)w_k(x)w_{k+1}(x)\in\mathbb Z[x].

These conjectures extend the paper's study of integrality and divisibility phenomena for Sun's generalized polynomials; their resolution is not specified in the supplied text.

Sources & referencesView supporting material

Primary source

Lin-Yue Li and Rong-Hua Wang, “q-Congruences for Z.-W. Sun's generalized polynomials w^(α)_k(x)”, arXiv:2507.04653 (2025).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.