The two-test hom-counting conjecture for finite groups

Let G1G_1 and G2G_2 be finite groups. For a finite group GG, write hG(H)h_G(H) for the number of group homomorphisms from GG to HH, and hG(H)h^G(H) for the number of group homomorphisms from HH to GG.

Two-test hom-counting conjecture. The following are equivalent:

  1. There is an isomorphism G1G2G_1\cong G_2.
  2. hG1(Gi)=hG2(Gi)h_{G_1}(G_i)=h_{G_2}(G_i) for i=1,2i=1,2.
  3. hG1(Gi)=hG2(Gi)h^{G_1}(G_i)=h^{G_2}(G_i) for i=1,2i=1,2.

The conjecture proposes that testing homomorphism counts only on G1G_1 and G2G_2 suffices to distinguish any two non-isomorphic finite groups, in both covariant and contravariant directions; the preceding results establish existence of a finite distinguishing test group but do not identify one of these two groups as sufficient.

Sources & referencesView supporting material

Primary source

Antonio Ceres, Cristina Costoya and Antonio Viruel, “Hom-counting functions, combinatorial categories and related problems”, arXiv:2506.01501 (2025).

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