Conjecture on prime values of polynomial floor sequences

About 1 year old · traced to

Let tt and dd be positive integers, with tt odd and d≥2d\geq 2. Consider the integer sequence with general term

⌊ntd⌋.\left\lfloor\frac{n^t}{d}\right\rfloor.

Prime-value conjecture for odd powers. (a) If t≡0(mod3)t\equiv 0\pmod 3 and d≠2,9d\neq 2,9, then there are infinitely many primes of the form

⌊ntd⌋.\left\lfloor\frac{n^t}{d}\right\rfloor.

(b) If t≢0(mod3)t\not\equiv 0\pmod 3 and d≠2d\neq 2, then there are infinitely many primes of the form

⌊ntd⌋.\left\lfloor\frac{n^t}{d}\right\rfloor.

The paper has already established that the excluded cases d=2d=2 and, when 3∣t3\mid t, d=9d=9 yield eventually prime-free sequences. The conjecture proposes that these are the only such exceptions among odd exponents, while the asserted infinitude of prime values remains open.

References

Primary source

Dan Ismailescu and Yunkyu James Lee, “Polynomially growing integer sequences all whose terms are composite”, arXiv:2501.04851 (2025).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.