Maximum-perimeter convex subset conjecture for triangles

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Let Ω\Omega be a triangle with vertices AA, BB, and CC. Assume that its diameter is the side [AB][AB] and that CAB^≥CBA^\widehat{CAB}\geq\widehat{CBA}. For c∈[0,∣Ω∣]c\in[0,|\Omega|], consider convex subsets ω⊂Ω\omega\subset\Omega with area ∣ω∣=c|\omega|=c. Triangle maximizer conjecture. The solution of

max⁡{P(ω)∣ω is convex, ω⊂Ω, ∣ω∣=c}\max\{P(\omega)\mid \omega\text{ is convex},\ \omega\subset\Omega,\ |\omega|=c\}

is the triangle MABMAB, where M∈[AC]M\in[AC] and its area is equal to c∣Ω∣c|\Omega|. This conjecture specifies the optimizer for the perimeter-maximization problem in a triangular container; the supplied evidence marks it as resolved, although the excerpt does not state the result resolving it.

References

Primary source

Zakaria Fattah, Ilias Ftouhi and Enrique Zuazua, “Optimal L^p-approximation of convex sets by convex subsets”, arXiv:2501.00928 (2025).

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