The finite-map criterion for properness
The finite-map criterion for properness
Let be a map of finite topological spaces. Say that a fibre has two points bounded above but not below when its two points have a common upper bound but no common lower bound, and say that two points are topologically indistinguishable when they have the same open neighbourhoods. The finite-map properness conjecture. The class is the class of all proper maps if and only if is closed, not surjective, and satisfies all of the following: has a fibre with two points bounded above but not below; has a fibre with two distinct topologically indistinguishable points; and the image of is not both open and closed. This is a proposed classification of the finite maps whose double orthogonal is exactly the class of proper maps; the source gives no proof or resolution.
Sources & referencesView supporting material
Primary source
Misha Gavrilovich, “Finite combinatorics implicit in the basic definitions of topology”, arXiv:2409.20464 (2024).
Progress summary
Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.
Solutions 0
Sign in to submit a solution.
No solutions have been posted yet.