The heuristic for the oblong cubic surface

Let k>1k>1 be a square-free integer, and let UA3U\subset\mathbb{A}^3 be the cubic surface

x3+ky3+kz3=1.x^3+ky^3+kz^3=1.

Let D(R)D(\mathbb{R}) denote the real component appearing in the paper's heuristic, and let U(AZfin)U(\mathbf{A}^{\mathrm{fin}}_{\mathbb{Z}}) denote the finite integral adelic points. Then γU\gamma_U is the exponent in the paper's main heuristic.

Oblong-surface conjecture. The main heuristic holds with

γU=38\gamma_U=\frac{3}{8}

and

V=D(R)×U(AZfin).V=D(\mathbb{R})\times U(\mathbf{A}^{\mathrm{fin}}_{\mathbb{Z}}).

The source presents this as a concrete test of the heuristic; it notes that b=1b=1 and ϱU=2\varrho_U=2 for this surface, but supplies no resolution status.

Sources & referencesView supporting material

Primary source

Tim Browning and Florian Wilsch, “Integral points on cubic surfaces: heuristics and numerics”, arXiv:2407.16315 (2024).

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