The restriction conjecture for the paraboloid

About 2 years old · traced to

Let Pn−1⊆Rn\mathbb P^{n-1}\subseteq\mathbb{R}^n be the truncated paraboloid

Pn−1={(ω′,∣ω′∣2):∣ω′∣≤1}.\mathbb P^{n-1}=\{(\omega',|\omega'|^2):|\omega'|\leq 1\}.

Define its extension operator by

Ef(x):=∫Pn−1eiωxf(ω) dvolPn−1(ω).Ef(x):=\int_{\mathbb P^{n-1}}e^{i\omega x}f(\omega)\,d\mathrm{vol}_{\mathbb P^{n-1}}(\omega).

Restriction conjecture. The estimate

∥Ef∥Lp(Rn)≲∥f∥Lp(Pn−1)\|Ef\|_{L^p(\mathbb{R}^n)}\lesssim\|f\|_{L^p(\mathbb P^{n-1})}

holds for p>2nn−1p>\frac{2n}{n-1}. This is presented as the restriction conjecture in dimension nn, arising from polynomial-partitioning methods and intended to describe the sharp range of exponents for the paraboloid extension estimate. The source gives no resolution status or further account of what remains open.

Equivalent formulations 1Other wordings

Other statements of this same problem, merged from separate entries. Each is equivalent to the statement above — proving any one settles them all.

  1. The restriction conjecture for the paraboloid

    Let f ⁣:[−1,1]d−1→Cf\colon[-1,1]^{d-1}\to\mathbb{C}, and let EfEf denote the extension operator for the paraboloid. Paraboloid restriction conjecture. For each q>2dd−1q>\frac{2d}{d-1} and each f ⁣:[−1,1]d→Cf\colon[-1,1]^d\to\mathbb{C}, we have

    ∥Ef∥q≲q,d∥f∥∞.\Vert Ef\Vert_q\lesssim_{q,d}\Vert f\Vert_\infty.

    This is a central conjecture in Fourier restriction theory. The supplied text gives no resolution status, so its status is left open.

    source: Joshua Zahl, “A discretized Severi-type theorem with applications to harmonic analysis”, arXiv:1801.05106 (2021).

References

Primary source

John Green, Terry Harris, Kaiyi Huang and Arian Nadjimzadah, “A Study Guide for "A Restriction Estimate using Polynomial Partitioning"”, arXiv:2402.03470 (2024).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.