Freeness conjecture for the symmetric algebra of a nilradical
Freeness conjecture for the symmetric algebra of a nilradical
Let be a simple Lie algebra, let be a nilradical in , and let be the maximal unipotent subgroup associated with the chosen Borel subgroup. Write for the symmetric algebra of , and let denote the Poisson centre associated with an optimal nilradical . Freeness conjecture. For any nilradical in a simple Lie algebra , is a free -module. In particular, for any optimal nilradical , is a free -module. The statement is suggested by the computations preceding it; the supplied text does not establish it in general, so its general validity remains open.
Sources & referencesView supporting material
Primary source
Dmitri I. Panyushev, “The Frobenius semiradical, generic stabilisers, and Poisson centre for nilradicals”, arXiv:2310.18945 (2023).
Progress summary
Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.
Solutions 0
Sign in to submit a solution.
No solutions have been posted yet.