The mock plectic invariant rank-distribution conjecture

About 3 years old · traced to

Let KK be a quadratic imaginary field, let E/QE/\mathbb Q be the elliptic curve in the construction, let E′E' be its quadratic twist attached to KK, and let Capricorn(τ)\text{Capricorn}(\tau) denote the mock plectic invariant. Mock plectic invariant rank-distribution conjecture. If L(E/K,1)=0L(E/K,1)=0, then

Capricorn(τ)≠0⟺{ralg(E/Q)=0, ralg(E′/Q)=2,if ap(E)=+1,ralg(E/Q)=1, ralg(E′/Q)=1,if ap(E)=−1.\text{Capricorn}(\tau)\ne0\quad\Longleftrightarrow\quad \begin{cases} r_{\mathrm{alg}}(E/\mathbb Q)=0,\ r_{\mathrm{alg}}(E'/\mathbb Q)=2,&\text{if }a_p(E)=+1,\\ r_{\mathrm{alg}}(E/\mathbb Q)=1,\ r_{\mathrm{alg}}(E'/\mathbb Q)=1,&\text{if }a_p(E)=-1. \end{cases}

This conjecture predicts when the mock plectic invariant is nonzero in the rank-two setting, with the distribution between the two quadratic eigenspaces governed by the reduction type at pp. Its status is not resolved in the source.

References

Primary source

Henri Darmon and Michele Fornea, “Mock plectic points”, arXiv:2310.16758 (2023).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.