The prime-square conjecture for the unit-fraction Maker–Breaker game

Let kk be a positive integer and let pp be an odd prime such that k+1=p2k+1=p^2. Let f(k,1)f(k,-1) denote the least board size for which Maker can force a solution to the unit-fraction equation

1x1++1xk=1y\frac{1}{x_1}+\cdots+\frac{1}{x_k}=\frac{1}{y}

with the variables not necessarily distinct. Prime-square conjecture. If k+1=p2k+1=p^2 for some odd prime pp, then

f(k,1)=k+2.f(k,-1)=k+2.

The equality is proved when k+1k+1 is an odd prime, but the authors state that they cannot verify the prime-square case and believe it should hold.

Sources & referencesView supporting material

Primary source

Collier Gaiser and Paul Horn, “Maker-Breaker Rado games for equations with radicals”, arXiv:2309.09145 (2024).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.