Strict dyadic Swan-exponent inequality for irreducible orthogonal representations
Let be the relevant local Galois group, let be its residue characteristic, and let be a finite-dimensional Galois representation. Write for its Swan conductor, and write and for its symmetric and exterior square representations. A representation is orthogonal if it admits a nondegenerate -invariant symmetric bilinear form, and it is tame if its wild inertia subgroup acts trivially.
Strict inequality conjecture. Assume . For any irreducible orthogonal Galois representation of which is not tame, one has
This is presented as a further expected consequence supported by the paper's induction argument and is not proved in general.
References
Primary source
Guy Henniart and Masao Oi, “On Swan exponents of symmetric and exterior square Galois representations”, arXiv:2307.15248 (2023).
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