Poissonian gap distribution conjecture for
Let and let satisfy and . For each , let be an ordering of the points with . Poissonian gap distribution conjecture. The normalized consecutive gaps satisfy
In other words, the gap distribution should be Poissonian. The case is excluded because the gap distribution is known not to be Poissonian there; this is also the only case in which existence of the gap distribution is known.
References
Primary source
Maksym Radziwiłł and Andrei Shubin, “Poissonian pair correlation for αn^θ”, arXiv:2304.04621 (2023).
Progress summary
Never refreshed
Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.
Solutions 0
No solutions have been posted yet.