Berry's conjecture on the variance of zeta zeros

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Let S(t)S(t) be the argument function of the Riemann zeta function, and let γ0\gamma_0 be Euler's constant. For δ>0\delta>0, consider the mean square of the increment S(t+2πδ/log⁡T)−S(t)S(t+2\pi\delta/\log T)-S(t). Berry's conjecture. As T→∞T\to\infty, the following asymptotic formulae hold:

(a) If δ=o(log⁡T)\delta=o(\log T), then

∫0T[S(t+2πδlog⁡T)−S(t)]2 dt=Tπ2[log⁡(2πδ)−Ci⁡(2πδ)−2πδSi⁡(2πδ)+π2δ−cos⁡(2πδ)+1+γ0]+o(T).\int_0^T\left[S\left(t+\frac{2\pi\delta}{\log T}\right)-S(t)\right]^2\,\mathrm{d}t=\frac{T}{\pi^2}\left[\log(2\pi\delta)-\operatorname{Ci}(2\pi\delta)-2\pi\delta\operatorname{Si}(2\pi\delta)+\pi^2\delta-\cos(2\pi\delta)+1+\gamma_0\right]+o(T).

(b) If δ≫log⁡T\delta\gg\log T, then

∫0T[S(t+2πδlog⁡T)−S(t)]2 dt=Tπ2[∑n≤TΛ2(n)nlog⁡2n(1−cos⁡(2πδlog⁡nlog⁡T))+1]+o(T).\int_0^T\left[S\left(t+\frac{2\pi\delta}{\log T}\right)-S(t)\right]^2\,\mathrm{d}t=\frac{T}{\pi^2}\left[\sum_{n\leq T}\frac{\Lambda^2(n)}{n\log^2 n}\left(1-\cos\left(\frac{2\pi\delta\log n}{\log T}\right)\right)+1\right]+o(T).

Here Λ\Lambda is the von Mangoldt function, Si⁡(x)=∫0xsin⁡uu du\operatorname{Si}(x)=\int_0^x\frac{\sin u}{u}\,\mathrm{d}u, and Ci⁡(x)=−∫x∞cos⁡uu du\operatorname{Ci}(x)=-\int_x^\infty\frac{\cos u}{u}\,\mathrm{d}u. The universal regime in part (a) was proved by Fujii assuming RH and Montgomery's strong pair correlation conjecture. Assuming RH and Chan's longer-range version of that conjecture, the paper verifies both parts in the range δ=o(log⁡4/3T)\delta=o(\log^{4/3}T); part (b) may hold in a longer range.

References

Primary source

Meghann Moriah Lugar, Micah B. Milinovich and Emily Quesada-Herrera, “On the number variance of zeta zeros and a conjecture of Berry”, arXiv:2211.14918 (2022).

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