Negative surface curvature implies hyperbolicity

From papers

Let XX be a finite, standard, irreducible 2-complex, and let σ+(X)\sigma_+(X) denote its positive surface curvature invariant.

Negative surface curvature implies hyperbolicity. If σ+(X)<0\sigma_+(X)<0 then π1(X)\pi_1(X) is word-hyperbolic.

The conjecture is presented as a common generalisation of Greendlinger's lemma and the B.B. Newman spelling theorem. The source notes unresolved issues for non-positively curved Euclidean 2-complexes and one-relator presentation complexes; no resolution is supplied.

Progress summary

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Sources & referencesView supporting material

Primary source

Henry Wilton, “Rational curvature invariants for 2-complexes”, arXiv:2210.09853 (2024).

Solutions 0

No solutions have been posted yet.