Quadruple equidistribution conjecture for ascent-sequence statistics

From papers

Let An\mathcal{A}_n be the set of ascent sequences of length nn, and let asc\mathsf{asc}, rep\mathsf{rep}, zero\mathsf{zero} and max\mathsf{\max} denote their ascent-sequence statistics.

Quadruple equidistribution conjecture. For every n1n\geq1,

sAnuasc(s)xrep(s)zzero(s)qmax(s)=sAnurep(s)xasc(s)zmax(s)qzero(s).\sum_{s\in\mathcal{A}_n}u^{\mathsf{asc}(s)}x^{\mathsf{rep}(s)}z^{\mathsf{zero}(s)}q^{\mathsf{\max}(s)}=\sum_{s\in\mathcal{A}_n}u^{\mathsf{rep}(s)}x^{\mathsf{asc}(s)}z^{\mathsf{\max}(s)}q^{\mathsf{zero}(s)}.

Equivalently, the statistic quadruples (asc,rep,zero,max)(\mathsf{asc},\mathsf{rep},\mathsf{zero},\mathsf{\max}) and (rep,asc,max,zero)(\mathsf{rep},\mathsf{asc},\mathsf{\max},\mathsf{zero}) are equidistributed on ascent sequences. The source states that this conjecture is affirmed in the paper, so it is no longer open.

Progress summary

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Sources & referencesView supporting material

Primary source

Emma Yu Jin, “Symmetric generating functions and Euler-Stirling statistics on permutations”, arXiv:2210.08789 (2022).

Solutions 0

No solutions have been posted yet.