The bi-LFS/bi-UFS equivalence conjecture for positive semidomains

Let SS be a positive semidomain. It is a bi-LFS if both (S,+)(S,+) and SS^\bullet are length-factorial monoids (LFMs), and a bi-UFS if both (S,+)(S,+) and SS^\bullet are unique-factorization monoids (UFMs). Bi-LFS/bi-UFS equivalence conjecture. SS is a bi-LFS if and only if it is a bi-UFS. This conjecture would greatly restrict the possibilities for counterexamples to the question of whether N0\mathbb{N}_0 is the only positive subsemidomain of R\mathbb{R} that is a bi-LFS.

Sources & referencesView supporting material

Primary source

Alan Bu, Joseph Vulakh and Alex Zhao, “Length-Factoriality and Pure Irreducibility”, arXiv:2210.06638 (2024).

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