The free-group conjecture on Fourier multipliers outside the Fourier–Stieltjes closure

Let G=FnG=\mathbb{F}_n be the free group with n2n{\geqslant} 2. Let VN(Fn)\operatorname{VN}(\mathbb{F}_n) be its group von Neumann algebra, and let MφM_\varphi denote the completely bounded Fourier multiplier associated with a multiplier function φ\varphi. Write B(G)cb\overline{\operatorname{B}(G)}^{\mathrm{cb}} for the closure of the Fourier–Stieltjes algebra in the space of completely bounded Fourier multipliers.

Free-group Fourier multiplier conjecture. There exists a completely bounded Fourier multiplier

Mφ:VN(Fn)VN(Fn)M_\varphi:\operatorname{VN}(\mathbb{F}_n)\to\operatorname{VN}(\mathbb{F}_n)

which does not belong to B(G)cb\overline{\operatorname{B}(G)}^{\mathrm{cb}}.

For discrete groups, decomposable Fourier multipliers coincide isometrically with the Fourier–Stieltjes algebra, so the conjecture would produce a completely bounded multiplier that is strongly non-decomposable. The source does not state a resolution.

Sources & referencesView supporting material

Primary source

Cédric Arhancet and Christoph Kriegler, “Decomposable Fourier Multipliers and an Operator-Algebraic Characterization of Amenability”, arXiv:2205.13823 (2025).

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