The free-group conjecture on Fourier multipliers outside the Fourier–Stieltjes closure
The free-group conjecture on Fourier multipliers outside the Fourier–Stieltjes closure
Let be the free group with . Let be its group von Neumann algebra, and let denote the completely bounded Fourier multiplier associated with a multiplier function . Write for the closure of the Fourier–Stieltjes algebra in the space of completely bounded Fourier multipliers.
Free-group Fourier multiplier conjecture. There exists a completely bounded Fourier multiplier
which does not belong to .
For discrete groups, decomposable Fourier multipliers coincide isometrically with the Fourier–Stieltjes algebra, so the conjecture would produce a completely bounded multiplier that is strongly non-decomposable. The source does not state a resolution.
Sources & referencesView supporting material
Primary source
Cédric Arhancet and Christoph Kriegler, “Decomposable Fourier Multipliers and an Operator-Algebraic Characterization of Amenability”, arXiv:2205.13823 (2025).
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