Odd-weight evaluation conjecture for multiple tt-values

Let t\sfrac1 ⁣2(2,{1}2n+1,2)t^{\sfrac{1\!}{2}}(2,\{1\}^{2n+1},2) denote the multiple tt-value with the indicated indices, and let t(k)t(k) denote the ordinary tt-value of weight kk. Odd-weight evaluation conjecture. For every nonnegative integer nn,

t\sfrac1 ⁣2(2,{1}2n+1,2)=4+2n23+2nt(5+2n).t^{\sfrac{1\!}{2}}(2,\{1\}^{2n+1},2)=\frac{4+2n}{2^{3+2n}}t(5+2n).

This conjecture gives the odd-weight analogue of the preceding even-weight evaluation. The text notes that the usual symmetry theorem likely cannot establish it because t(2n+1)t(2n+1) is conjecturally irreducible, so a new technique is needed.

Sources & referencesView supporting material

Primary source

Steven Charlton and Michael E. Hoffman, “Symmetry results for multiple t-values”, arXiv:2204.14183 (2022).

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