The equal-order correspondence conjecture for polycyclic codes associated with trinomials
Let and satisfy
Let be the set of all polycyclic codes of length over associated with , and let be the corresponding set for . The equal-order correspondence conjecture. The sets and are in one-to-one correspondence, with corresponding codes equivalent to each other. The source paper states that the original conjecture is incorrect and gives a counterexample, so this claim is refuted in the source context.
References
Primary source
Minjia Shi, Haodong Lu, Shuang Zhou, Jiarui Xu and Yuhang Zhu, “Equivalence and Duality of Polycyclic Codes Associated with Trinomials over Finite Fields”, arXiv:2204.12433 (2022).
Progress summary
The conjecture is false: a published counterexample shows that equal polynomial order does not guarantee the proposed correspondence.
The conjecture appeared as Conjecture in a paper on polycyclic codes associated with trinomials, motivated by computational evidence. It asserted a one-to-one correspondence between the two code families, preserving code equivalence, whenever the defining trinomials have equal order.
Known results
- The original equal-order condition was proposed as a conjecture, not proved, in .
- A corrected theorem replaces equal order by the reciprocal relation and establishes the desired correspondence under that stronger hypothesis.
2022 counterexample
The later paper states that Conjecture is incorrect. Over , it uses and , both of order , but their associated families contain respectively and linear codes; hence the conjectured correspondence cannot exist. The work was listed with metadata and later publication information.
Current status (as of August 2026): The original equal-order correspondence conjecture is settled as false, while the stronger reciprocal-polynomial correspondence is the valid replacement.
Solutions 0
No solutions have been posted yet.