Conjecture on definiteness of separable symmetric tensors

Let v1,v2,,vmRn\textbf{v}_{1},\textbf{v}_{2}, \ldots,\textbf{v}_{m}\in \mathbb R^{n} with nmn\ge m be linearly independent vectors, and let

A=v1v2vm.\mathcal{A}=\textbf{v}_{1}\vee \textbf{v}_{2}\vee \ldots \vee\textbf{v}_{m}.

Definiteness conjecture. Then A\mathcal{A} is neither a positive semidefinite tensor nor a negative semidefinite tensor.

This conjectures that the conclusion established for separable symmetric tensors of order two extends to all orders m2m\ge 2. The source gives no resolution beyond the order-two lemma, so the general statement remains open.

Sources & referencesView supporting material

Primary source

Changqing Xu, “Separable symmetric tensors and separable anti-symmetric tensors”, arXiv:2202.12792 (2022).

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